-2-16A=-6x^2+9x+2

Solution for -2-16A=-6x^2+9x+2 equation:

-2-16=-6A^2+9A+2

We move all terms to the left:

-2-16-(-6A^2+9A+2)=0

We add all the numbers together, and all the variables

-(-6A^2+9A+2)-18=0

We get rid of parentheses

6A^2-9A-2-18=0

We add all the numbers together, and all the variables

6A^2-9A-20=0

a = 6; b = -9; c = -20;
Δ = b2-4ac
Δ = -92-4·6·(-20)
Δ = 561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{561}}{2*6}=\frac{9-\sqrt{561}}{12}
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{561}}{2*6}=\frac{9+\sqrt{561}}{12}
$